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Find area of a triangle two sides of which are 18cm and 10cm and the perimeter is 42cm |
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Answer» 21√11 Yes 21√11cm² Let side of triangle is a,b and ca= 18cmb= 10cmc= xPerimeter of triangle= a+b+c42=18+10+x42=28+xx= 42-28x=14So, c=14semi perimeter=a+b+c/2 18+10+14/2 42/2=21area of triangle by heron\'s formula√s(s-a)(s-b)(s-c)√21(21-18)(21-10)(21-14)√21x3x11x7√3x7x3x11x7 (pair by of 3 and 7)3x7√11Ans-21√11 |
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