Find area of triangle whose two sides are 18 cm and 10 cm .periemeter

1.	Find area of triangle whose two sides are 18 cm and 10 cm .periemeter is 42 cm
Answer» Answer is 21 underroot 11 cm sq. I solve it with the herons formula and the answer is 11√21 cm^2 Given,Side a=18cmSide b=10cmPerimeter=42cm=a+b+c:. Putting value42=18+10+c42=28+c42-28=c14=cNow,S=(a+b+c)/2:. Putting valueS=42/2S=21Now according to Heron\'s formula-Area of a triangle=√{s(s-a)(s-b)(s-c)}:. Putting value=√{21(21-18)(21-10)(21-14)}=√{21(3)(11)(7)}=√4851=21√11cm²

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