1.

Find centre of mass of given rod of linear mass density `lambda=(a+b(x/l)^2)` , x is distance from one of its end. Length of the rod is `l`.A. `4/3((a+b)/(2a+3b))L`B. `3/2((a+b)/(2a+b))L`C. `3/2((2a+b)/(3a+b))L`D. `3/4((2a+b)/(3a+b))L.`

Answer» Correct Answer - 4


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