1.

Find centre of mass of given rod of linear mass density `lambda=(a+b(x/l)^2)` , x is distance from one of its end. Length of the rod is `l`.A. `(3l)/4((3a+b)/(2a+b))`B. `(3l)/4((2a+b)/(3a+b))`C. `(l)/4((2a+b)/(3a+b))`D. `l((2a+b)/(3a+b))`

Answer» Correct Answer - B


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