1.

Find coordinates of the point on the parabola. Also, find focal distance: y2 = 12x whose parameter is 1/3

Answer»

Given equation of the parabola is y2 = 12x. Comparing this equation with y2 = 4ax, we get 

⇒ 4a = 12 

⇒ a = 3 

If t is the parameter of the point P on the parabola, then 

P(t) = (at2 , 2at) 

i.e., x = at2 and y = 2at ……..(i)

Given, t = 1/3

Substituting a = 3 and t = 1/3 in (i), we get 

x = 3 (1/3)and y = 2(3)(1/3)

x = 1/3 and y =2

The co-ordinates of the point on the parabola are (1/3, 2)

∴ Focal distance = x + a

= 1/3 + 3

= 10/3



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