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    				| 1. | Find coordinates of the point on the parabola. Also, find focal distance: y2 = 12x whose parameter is 1/3 | 
| Answer» Given equation of the parabola is y2 = 12x. Comparing this equation with y2 = 4ax, we get ⇒ 4a = 12 ⇒ a = 3 If t is the parameter of the point P on the parabola, then P(t) = (at2 , 2at) i.e., x = at2 and y = 2at ……..(i) Given, t = 1/3 Substituting a = 3 and t = 1/3 in (i), we get x = 3 (1/3)2 and y = 2(3)(1/3) x = 1/3 and y =2 The co-ordinates of the point on the parabola are (1/3, 2) ∴ Focal distance = x + a = 1/3 + 3 = 10/3 | |