1.

Write the coordinates of the focus of parabola x2 – 4x – 8y = 4.

Answer»

Equation of parabola,

x2 – 4x – 8y = 4

⇒ x2 – 2.2x + (2)2 = 8y + 4 + 22

⇒ (x – 2)2 = 8y + 8

= 8(y + 1)

(x-2)2 = 4.2.(y + 1)

x2 = 4.2.y

Where x = x – 2 and Y = y + 1

a = 2

Coordinates of focus = (0, a)

x = x- 2 = 0

⇒ x = 2

Y = y + 1 = 2

⇒ y = 1

Thus coordinates of focus = (2, 1)



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