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    				| 1. | Write the coordinates of the focus of parabola x2 – 4x – 8y = 4. | 
| Answer» Equation of parabola, x2 – 4x – 8y = 4 ⇒ x2 – 2.2x + (2)2 = 8y + 4 + 22 ⇒ (x – 2)2 = 8y + 8 = 8(y + 1) (x-2)2 = 4.2.(y + 1) x2 = 4.2.y Where x = x – 2 and Y = y + 1 a = 2 Coordinates of focus = (0, a) x = x- 2 = 0 ⇒ x = 2 Y = y + 1 = 2 ⇒ y = 1 Thus coordinates of focus = (2, 1) | |