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Find delta f and df when f(x) = 2x^2 - 1, x = 1, delta x = 0 cdot 02 |
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Answer» SOLUTION : `f(x) = 2x^2 - 1, x = 1, delta x = 0 cdot 02` Then `delta f = f(x+ Delta x) - f(x)` =f(1.02) - f(1) = `2 (1 cdot 02)^2 - 1 - (2- 1)` =`2 cdot 0808 - 2 = 0 cdot 0808` Again `df= 4X DX = 4 xx 1 xx 0 cdot 02 = 0 cdot 08` |
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