1.

Find delta f and df when f(x) = (x+1)^3 , x =8, deltax = 0.04

Answer»

Solution :`f(X) = (x+1)^3 , x =8, deltax = 0.04`
`deltaf = f(x+deltax)-f(x)`
= `(9.04)^3 - (8+1)^3`
`= (9.04)^3 -9^3 = 9.7632`
Again `DF = (3x+1)^2 dx = 3 xx 9^2 xx 0.04`
`243 xx 0.04 = 9.72`


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