1.

Find delta f and df whenf(x) = sqrtx , x = 16, deltax = 0.3

Answer»

Solution :`F(x) = sqrtx , x = 16, deltax = 0.3`
`deltaf = f(x+deltax)-f(x) = sqrt(x+deltax)-sqrtx`
`= sqrt16.3 - sqrt16 = 4.0373-4`
= 0.373
Again DF = `1/(2sqrtx) dx = `1/(2sqrt16) xx 0.3`
= (0.3)/8 = 0.0375


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