1.

Find delta f and dfwhen f(x) = In (1+x), x = 1, deltax = 0.04

Answer»

Solution :`DELTAF = F(x+deltax)-f(x)`
= In `(1 + x + deltax)` - In(1+x)
In (2.04) - In (2) = 0.0198
Again df = 1/(1+x)dx = `1/2 XX 0.04 = 0.02`


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