1.

Find derivatives of the following functions. 1/(x^3 + sinx)^2

Answer»

SOLUTION :`y = 1/{(x^3 + SINX)^2} = (x^3 + sinx)^(-2)
dy/dx = -2(x^3 + sinx)^(-3)XX d/dx (x^3 + sinx)
= -2/{(x^2 + sinx)^3}.(3x^2 + cosx)
-{2(3x^2 + cosx)}/{(x^3 + sinx)^3}`


Discussion

No Comment Found

Related InterviewSolutions