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Find derivatives of the following functions. 1/(x^3 + sinx)^2 |
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Answer» SOLUTION :`y = 1/{(x^3 + SINX)^2} = (x^3 + sinx)^(-2) dy/dx = -2(x^3 + sinx)^(-3)XX d/dx (x^3 + sinx) = -2/{(x^2 + sinx)^3}.(3x^2 + cosx) -{2(3x^2 + cosx)}/{(x^3 + sinx)^3}` |
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