Saved Bookmarks
| 1. |
Find dy/dx if y=e²×sinx |
|
Answer» we should find \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x \) \( \frac{\mathrm{d}}{\mathrm{d}x}\mathrm{e}^2 \times \sin x=\mathrm{e}^2 \frac{\mathrm{d}}{\mathrm{d}x} \sin x=\mathrm{e}^2 \cos x \) y = e2x sin x \(\frac{dy}{dx}\) = e2x d/dx sin x + (d/dx e2x) sin x (By UV formula) = e2x cos x + 2 e2x sin x (By chain rule) = e2x(cos x+2 sin x) |
|