1.

Find (dy)/(dx) ify+siny=cosx

Answer»

Solution :`y+siny=cosx` DIFFERENTIATING THROUGHOUT w.r.y.x we GET `(dy)/(DX)+cosy(dy)/(dx)=-sinx(dy)/(dx)(1+cosy)=-sinx(dy)/(dx)=(-sinx)/(1+cosy)` where `cosyne-1`


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