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Find dy/dx,x=a cos'theta',y=a sin theta.

Answer»

SOLUTION :`x=a cos theta,y=a SIN theta `
Then `DX/(d theta)=-a sin theta `
`DY/(d theta)=a cos theta fracdy/d theta`
`dy/dx=(dy/(d theta))/((dx)/(d theta))=(a COSTHETA)/(-a sin theta) =-cot theta`


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