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Find dy/dx,x=a cos'theta',y=a sin theta. |
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Answer» SOLUTION :`x=a cos theta,y=a SIN theta ` Then `DX/(d theta)=-a sin theta ` `DY/(d theta)=a cos theta fracdy/d theta` `dy/dx=(dy/(d theta))/((dx)/(d theta))=(a COSTHETA)/(-a sin theta) =-cot theta` |
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