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Find dy/dxifxy=e^((x-y))

Answer»

SOLUTION :`LOG(XY)=(X-y)LOGE` `logx+logy=x-y` `1/x+1/ydy/dx=1-dy/dx` `(1/y+1)dy/dx=1-1/x` `dy/dx=(1-1/x)/(1+1/y)=((x-1)/x)/((y+1)/y)="y(x-1)"/(x(y+1))`


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