1.

Find each of the following products: (2x2 + 3x – 7) × (3x2 – 5x + 4)

Answer»

By using horizontal method, 

We have; 

(2x2+ 3x – 7) ×(3x2 – 5x + 4) 

= 2x2(3x2 – 5x + 4) + 3x(3x2 – 5x + 4) – 7(3x2 – 5x + 4) 

= 6x4 – 10x3 + 8x2 + 9x3 – 15x2 + 12x– 21x2 + 35x – 28 

Now, putting equal power terms together, we get, 

= 6x4 – 10x3 + 9x3 + 8x2 – 15x2– 21x2 + 35x + 12x– 28 

= 6x4 – x3 – 28x2 + 47x – 28


Discussion

No Comment Found

Related InterviewSolutions