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Find each of the following products:\((-\frac{1}{27}a^2b^2)\times (\frac{9}{2}a^3b^2c^2)\) |
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Answer» \(\frac{-1}{27}\times \frac{9}{2}\times a^2\times a^3\times b^2\times b^2\times c^2\) = \(\frac{-1}{6}\times a^5\times b^4\times c^2\) = \(\frac{-1}{6}a^5b^4c^2\) |
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