Find force of attraction between two objects and masses 6 multiple 10

1.	Find force of attraction between two objects and masses 6 multiple 10 power 24 kg and 7.4 multiple 10 power 22 kg and distance between them is 5 multiple 10 power 4
Answer» ANSWER: Hello Dear. Here is the answer--- Given Conditions ⇒ Mass of the Earth(m₁) = 6 × 10²⁴ kg. Mass of the Moon(m₂) = 7.4 × 10²² kg. Distance between the Earth and the Moon(d) = 3.84 × 10⁵ km. = 3.84 × 10⁸ m. Gravitational Constant(G) = 6.7 × 10⁻¹¹ Nm²/kg². Using the Newton's law of Gravitation, F = G × m₁× m₂ × /d². F is the Force of Gravitation between the Earth and the Moon. Substituting the Given Values in the FORMULA, ∴ F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 7.4 × 10²²) ÷ (3.84 × 10⁸)² ⇒ F = (6.7 × 6 × 7.4 × 10¹⁹) ÷ (14.7456) ⇒ F = 20.1741 × 10¹⁹ N. ⇒ F ≈ 20.2 × 10¹⁹ N. Thus, the Gravitational Force of Attraction between the Earth and the Sun is 20.2 × 10¹⁹ N. Hope it helps. 4.5

Find force of attraction between two objects and masses 6 multiple 10 power 24 kg and 7.4 multiple 10 power 22 kg and distance between them is 5 multiple 10 power 4

Answer»

Hello Dear.

Here is the answer---

Given Conditions ⇒

Mass of the Earth(m₁) = 6 × 10²⁴ kg.

Mass of the Moon(m₂) = 7.4 × 10²² kg.

Distance between the Earth and the Moon(d) = 3.84 × 10⁵ km.

= 3.84 × 10⁸ m.

Gravitational Constant(G) = 6.7 × 10⁻¹¹ Nm²/kg².

Using the Newton's law of Gravitation,

F = G × m₁× m₂ × /d².

F is the Force of Gravitation between the Earth and the Moon.

Substituting the Given Values in the FORMULA,

∴ F = (6.7 × 10⁻¹¹ × 6 × 10²⁴ × 7.4 × 10²²) ÷ (3.84 × 10⁸)²

⇒ F = (6.7 × 6 × 7.4 × 10¹⁹) ÷ (14.7456)

⇒ F = 20.1741 × 10¹⁹ N.

⇒ F ≈ 20.2 × 10¹⁹ N.

Thus, the Gravitational Force of Attraction between the Earth and the Sun is 20.2 × 10¹⁹ N.

Hope it helps.

4.5