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Find:\(\frac{dy}{dx} - e^{x-y} = e^{x-y}\)dy/dx - e(x-y) = e(x-y) |
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Answer» \(\frac{dy}{dx} - e^{x-y} = e^{x-y}\) ⇒ \(\frac{dy}{dx} = 2e^{x-y}\)----(i) Let x - y = t Then 1 - \(\frac{dy}{dx}=\frac{dt}{dx}\) \(\therefore\) \(\frac{dt}{dx} = 1-2e^t\) (From (i)) ⇒ \(\frac{dt}{1-2e^t}=dx\) ⇒ \(\frac{e^{-t}dt}{e^{-t}-2}=dx\) ⇒ \(\int\frac{e^{-t}}{e^{-t}-2}dt = \int dx\) ⇒ -log|e-t - 2| = x + c \(\therefore\) -log|e-(x - y) - 2| = x + c is a solution of given differential equation. |
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