1.

Find general value of `theta` which satisfies both `sin theta = -1//2` and `tan theta=1//sqrt(3)` simultaneously.

Answer» Here `sin theta lt 0` and `tan theta gt =0`, then `theta` lies in the third quadrant. Now
`sin theta=-1/2`
`rArr theta =pi+pi/6=(7pi)/6`
Generalizing, we have `theta=2npi+(7pi)/6, n in Z`.


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