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Find gof and fog if 1:R → R and g: R → R are given by f(x) = cosx and g(x) = 3x2 show that gof ≠ fog. |
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Answer» f(x) = cosx g(x) = 3x2 gof(x) = g[f(x)] = g[cosx] = 3cos2x fog(x) = f[g(x)] = f[3x2] = cos3x2 fog ≠ gof |
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