Find HCF and LCM of 404 and 96 and verify that HCF x LCM-Product of th

1.	Find HCF and LCM of 404 and 96 and verify that HCF x LCM-Product of the twogiven numbers
Answer» into prime factor s 404 = 2 × 2 × 101 = 2² × 101 96 = 2×2×2×2×2×3 = 2^5×3 HCF(404,96) = 2² = 4 [ Product of the smallest power of each common prime factors of the numbers ] LCM( 404,96) = 2^5 × 101 × 3 = 9696 ********************************** We know that , If h, l are HCF and LCM of two numbers a and b then l × h = a × b ********************************** Verification : l = 9696 , h = 4 , a = 404 , b = 96 l × h = 9696 × 4 = 38784 --(1) a × b = 404 × 96 = 38784---(2) Therefore , From (1) and (2) , we conclude that l × h = a × b

Find HCF and LCM of 404 and 96 and verify that HCF x LCM-Product of the twogiven numbers

Answer»

into prime factor s

404 = 2 × 2 × 101 = 2² × 101

96 = 2×2×2×2×2×3 = 2^5×3

HCF(404,96) = 2² = 4

[ Product of the smallest power

of each common prime factors

of the numbers ]

LCM( 404,96) = 2^5 × 101 × 3

= 9696

************************************

We know that ,

If h, l are HCF and LCM of

two numbers a and b then

l × h = a × b

************************************

Verification :

l = 9696 ,

h = 4 ,

a = 404 ,

b = 96

l × h = 9696 × 4 = 38784 --(1)

a × b = 404 × 96 = 38784---(2)

Therefore ,

From (1) and (2) , we conclude

that

l × h = a × b