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| 1. |
Find I for circuit shown below |
| Answer» Mesh Analysis Apply KVL at loop 2 125i2 - 100i3 = 0 ...(i) Apply KVL at loop 3 120i3 - 100i2 - 20i1 = 0 i1 = 5A ∴ 120i3 - 100i2 - 100 = 0 ∴ 120i3 - 100i2 = 100 ...(ii) From (i) 125i2 - 100i3 = 0 ...(iii) Put equation (iii) in eq. (ii) 120i 3 - 100i2 = 100 120 x - 100i2 = 100 150i2 - 100i2 = 100 ∴ 50i2 = 100 ∴ i2 = 2A. | |