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Find: i) \(\frac{7}{11}\) of 330 ii) \(\frac{5}{9}\) of 108 iii) \(\frac{2}{7}\) of 16 iv) \(\frac{1}{7}\) of \(\frac{3}{10}\) |
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Answer» i) \(\frac{7}{11}\) of 330 = \(\frac{7}{11}\) × 330 = \(\frac{7}{11}\) × 11 × 30 = 7 × 30 = 210 ii) \(\frac{5}{9}\) of 108 = \(\frac{5}{9}\) × 108 = \(\frac{5}{9}\) × 9 × 12 = 5 × 12 = 60 iii) \(\frac{2}{7}\) of 16 = \(\frac{2}{7}\) × 16 = \(\frac{2\times16}{7}\) = \(\frac{32}{7}\) or \(4\frac{4}{7}\) iv) \(\frac{1}{7}\) of \(\frac{3}{10}\) = \(\frac{1}{7}\) × \(\frac{3}{10}\) = \(\frac{1\times3}{7\times10}\) = \(\frac{3}{70}\) |
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