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Find(i) the lateral or curved surface area of a closed cylindrical petrol storage tank that is4.2 m in diameter and 4.5 m high.(ii) how much steel was actually used, if `1/(12)` of the steel actually used was wasted in making the tank |
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Answer» (i) Curved surface area =`2pirh=2xx(22)/(7)xx(4.2)/(2)xx4.5=5.9 m^(2)` (ii)Total steel used =Total surface area (Assuming thickness =0 m) `=2pir(r+h)` `=2xxx(22)/(7)xx(4.2)/(2)((4.2)/(2)+4.5)` `=(44)/(7)xx2.1xx(13.2)/(2)=22xx0.3xx13.2=87.12me^(2)` Let actural steel used is x `m^(2)` `(11)/(12)x=87.12` `x=(87.12xx12)/(11)=95.04 m^(2)` |
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