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Find `int_(0)^(1)picos((pi)/(2)t)dt=?`A. 6B. `pi`C. 2D. `(pi)/(2)` |
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Answer» Correct Answer - C `underset(0)overset(1)intpicos((pi)/(2)t)dt=pi[(2)/(pi)sin((pi)/(2)t)]_(0)^(1)2[sin.(pi)/(2)-sin0]=2` |
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