1.

Find`int(sin^6x)/(cos^8x)dxdot`A. `(tan^(6)x)/(6)+C`B. `(tan^(7)x)/(7)+C`C. `(tan^(8)x)/(8)+C`D. None of these

Answer» Correct Answer - B
We have,`" "l=int(sin^(6)x)/(cos^(8)x)dx`
`l=int((sinx)/(cosx))^(6)((1)/(cos^(2)x))dx`
`l=int tan^(6)x sec^(2)xdx`
Put `tanx=t rArr sec^(2) x dx = dt`
`therefore" "l=int t^(6)dt rArr l=(t^(7))/(7)+C`
`l=(tan^(7)x)/(7)+C`


Discussion

No Comment Found