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Find `intsin^(3)x cos^(5)x dx`. |
Answer» [Here, powers of both cos x and sin x are odd positive integers, therefore, put `z=cosx or z=sin x`, but the power of `cosx` is greater. Therefore, it is convenient to put `z=cosx`.] `intsin^(3)x cos^(5)x dx` `=intsin^(2)x cos^(5)xsin x dx` `=int(1-cos^(2)x)cos^(5)x sinx dx` `=int(1-z^(2))z^(5)(-dz)` `= -int(z^(5)-z^(7))dz` `= -((z^(6))/(6)-(z^(8))/(8))+c= -(cos^(6)x)/(6)+(cos^(8)x)/(8)+c` |
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