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Find least positive integer x, satisfying 276x+128=4 (mod 7). |
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Answer» Solution :Now 128 -= mod 7 Now `176 x+128 -=4 "mod" 7` `implies 176x -=(4-2)"mod" 7` `implies 176 x -=2 "mod" 7` `176 XX x=2 "mod" 7`, ` "But" 276 -= 3 "mod" 7,` `"THUS" x=3`. |
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