1.

Find least positive integer x, satisfying 276x+128=4 (mod 7).

Answer»

Solution :Now 128 -= mod 7
Now `176 x+128 -=4 "mod" 7`
`implies 176x -=(4-2)"mod" 7`
`implies 176 x -=2 "mod" 7`
`176 XX x=2 "mod" 7`,
` "But" 276 -= 3 "mod" 7,`
`"THUS" x=3`.


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