Saved Bookmarks
| 1. |
find minimum value of F such that `m_(2)` starts its motion on the ground A. `(mu_(0)(2m_(1)+m_(2))g)/(2)`B. `mu_(0)(2m_(1)+m_(2))g`C. `mu_(0)(m_(1)+m_(2))g`D. `(mu_(0)(m_(1)+m_(2))g)/(2)` |
|
Answer» Correct Answer - A `Fx-mu_(0)m_(1)gx-(1)/(2)kx^(2)=0` `x=(mu_(0)m_(2)g)/(k)` |
|