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`find normal force acting on block & value of force F for equilibrium of block ` |
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Answer» From the question we know that the block is in equilibrium so when we resolve the angle the force F makes with the horizontal we get Fcos60 is the force that keeps the block in equilibrium against the 100N force ,so 100N=Fcos60 100N=F/2 Therefore F=200N The normal force or normal reaction is again got got by resolving F Nr=Fsin60(where Nr is the normal reaction) Nr=200(√3)/2 Nr=100(√3)N |
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