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| 1. |
Find out %error of volume of cylinder if r=4% and h=6%? |
| Answer» V=πr^2hBy differentiatingdv/v=2*(dr/r)+(dh/h)Now by multiplying by 100 both side(dv/v)*100=2*(dr/r)*100+(dh/h)*100 %error in v=2*4%+6%=14% | |