Find out moment of inertia of a solid cylinder through its centre

1.	Find out moment of inertia of a solid cylinder through its centre
Answer» L2 = 3R2as\xa0MI of a solid cylinder about its own axis is ½ MR2and\xa0MI about an axis passing through its centre of gravity and perpendicular to its length isM(L2/12 + R2/4)\xa0½ MR2\xa0=\xa0M(L2/12 + R2/4)R2/2 =\xa0L2/12 + R2/4R2/2 – R2/4\xa0= L2/12L2\xa0= 3R2L1/2\xa0= 31/2\xa0R

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