Find out power of an engine which can extract coal at a rate of 5×10^

1.	Find out power of an engine which can extract coal at a rate of 5×10^5 kg/hour from a 200 m deep mine
Answer» Answer: this is the correct answer Explanation: Calculate the power of an engine required to lift 100000 KG of coal per hour from a mine 360m deep. Answer-----> Mass(m) = 100000 kg = 510^5 kg Height (h) = 200m Acceleration DUE to gravity = 10 m/s^2 Time(t) = 1 hour = 3600 s Then, P.E = mgh = 510^5 * 10 * 360 J Work done = P.E = 510^5 10 * 360 J We know, Power = Work done / Time = 510^5 x 10 x 360/3600 =5 10^5 watt. Hope It Helps You

Find out power of an engine which can extract coal at a rate of 5×10^5 kg/hour from a 200 m deep mine

Answer»

Answer:

this is the correct answer

Explanation:

Calculate the power of an engine required to lift 100000 KG of coal per hour from a mine 360m deep.

Answer----->

Mass(m) = 100000 kg = 5*10^5 kg

Height (h) = 200m

Acceleration DUE to gravity = 10 m/s^2

Time(t) = 1 hour = 3600 s

Then,

P.E = mgh

= 5*10^5 * 10 * 360 J

Work done = P.E = 5*10^5 * 10 * 360 J

We know,

Power = Work done / Time

= 5*10^5 x 10 x 360/3600

=5* 10^5 watt.

Hope It Helps You

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Find out power of an engine which can extract coal at a rate of 5×10^5 kg/hour from a 200 m deep mine

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