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Find out the angle made by `vecA=hati+hatj+hatk` vector from X,Y and Z axes respectively.

Answer» Given `A_(x)=A_(y)=A_(z)=1` so `A=sqrt(A_(x)^(2)+A_(y)^(2)+A_(z)^(2))=sqrt(1+1+1)=sqrt(3)`
`cos alpha =(A_(x))/(A)=(1)/sqrt(3)` or `alpha=cos^(-1)(1)/sqrt(3)`
`cos beta =(A_(y))/(A)=(1)/sqrt(3)` or `beta=cos^(-1)(1)/sqrt(3)`
`cos lambda=(A_(z))/(A)=(1)/sqrt(3)` or `lambda=cps^(-1)(1)/sqrt(3)`


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