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Find out the atomic number, mass number, number of protons, electrons and neutrons present in the element with the notation ._(92)^(238)U |
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Answer» SOLUTION :Atomic number (Z) = 92, Mass number (A) = 238 But we know that No. of protons = No. of electrons = Atomic number (Z) `:.` No. of protons = 92 and No. of electrons = 92 Further, No. of NEUTRONS = Mass number - Atomic number `A - Z= 238 - 92 = 146` |
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