Find out the EAN of(a) [Zn(NH3)4]2+(b) [Fe(CN)6]4+

1.	Find out the EAN of(a) [Zn(NH3)4]2+(b) [Fe(CN)6]4+
Answer» (a) For the complex ion, [Zn(NH₃)₄]²⁺ : Atomic number of Zn = Z = 30 Charge on metal ion = + 2 \(\therefore\) Number of electrons lost by Zn atom = X = 2 Total number of electrons donated by \(4NH^{2^3}\) ligands = Y = 2 x 4 = 8 EAN = Z – X + Y = 30 – 2 + 8 = 36 (Note : This is atomic number of the nearest inert element 3₆Kr.) (b) For the complex ion, [Fe(CN)J^4- : For Fe, Z = 26 (Atomic number) X = 2 (Due to + 2 charge on Fe) Y = 12 (Due to 6 CN^- ligands) ∴ EAN = Z – X + Y = 26 – 2 + 12 = 36

Answer»

(a) For the complex ion, [Zn(NH₃)₄]²⁺ :

Atomic number of Zn = Z = 30

Charge on metal ion = + 2

\(\therefore\) Number of electrons lost by Zn atom = X = 2 Total number of electrons donated by \(4NH^{2^3}\)

ligands = Y = 2 x 4 = 8

EAN = Z – X + Y

= 30 – 2 + 8

= 36

(Note : This is atomic number of the nearest inert element 3₆Kr.)

(b) For the complex ion, [Fe(CN)J^4- :

For Fe, Z = 26 (Atomic number)

X = 2 (Due to + 2 charge on Fe)

Y = 12 (Due to 6 CN^- ligands)

∴ EAN = Z – X + Y

= 26 – 2 + 12

= 36

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