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Find out the following in the electric circuit given figure (a)effective resistance of two 8 ohm resistor combination (b)current flowing through 4 ohm resistor (c) potential difference across 4 ohm resistance (d)power dissipated in 4ohm resistor (e) difference in ammeter reading,if any. |
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Answer» a.) 1/Rp= 1/8+1/8= 4 ohm. b.) CURRENT FLOWING through the circuit remains the same. EFFECTIVE Resistance= 4 ohm+ 4 ohm= 8ohm. V=IR 8=I*8 I=1 A. C.) V=IR V=1*4= 4 V. D.)P=VI P=1*4 4 W. E.) No there is no difference on the READING of the ammeter. |
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