1.

Find out the following in the electric circuit given figure (a)effective resistance of two 8 ohm resistor combination (b)current flowing through 4 ohm resistor (c) potential difference across 4 ohm resistance (d)power dissipated in 4ohm resistor (e) difference in ammeter reading,if any.

Answer»

a.) 1/Rp= 1/8+1/8= 4 ohm.

b.) CURRENT FLOWING through the circuit remains the same.

EFFECTIVE Resistance= 4 ohm+ 4 ohm= 8ohm.

V=IR

8=I*8

I=1 A.

C.) V=IR

V=1*4= 4 V.

D.)P=VI

P=1*4

4 W.

E.) No there is no difference on the READING of the ammeter.



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