1.

Find out the median size from the following:X160150152161156f58637

Answer»
Xfcumulative Frequency (cf)
15088
152614
156721
160526
161329
N = 29


Median = size of \((\frac{N+1}{2})^{th}\) item

Median = \(\frac{29+1}{2}= 15^{th}\)
When locating the item inCumulative Frequency column. The item that exceeded 15th is 21 corresponding to 156. Therefore, median is 156.



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