Find out the number of elections, protons and neutronfollowing40Ar18�

1.	Find out the number of elections, protons and neutronfollowing40Ar18
Answer» ANSWER:- The ELEMENT is ARGON here. The SYMBOL GIVEN by $\\ \sf\longmapsto 18^{Ar^{40}}$ Here Atomic mass=40 Atomic number=18 We know $\\ \sf\longmapsto No\:of\:protons=Atomic\:Number$ $\therefore\underline{\boxed{\bf No\:of\:Protons=18}}$ Again $\\ \sf\longmapsto No\:of\:protons=No\:of\:electrons$ $\therefore\underline{\boxed{\bf No\:of\:electrons=18}}$ And $\\ \sf\longmapsto No\:of\:Neutrons=Atomic\:Mass-No\:of\:Protons$ $\\ \sf\longmapsto 40-18=22$ $\therefore\underline{\boxed{\bf No\:of\:Neutrons=22}}$