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Find out the number of waves made by a Bohr electron in its 3rd orbit. |
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Answer» Solution :No. of waves in any ORBIT `= ("CIRCUMFERENCE of that orbit")/("Wavelength") = (2pi r)/(lamda) = (2pi r)/((h//mv)) = (2pi)/(h) (m v r) = (2pi)/(h) (NH)/(2pi) = n` Thus, the number of waved in 3RD orbit = 3 |
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