Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine. NaClO_(4),NaClO_(3),NaClO,KClO_(2),Cl_(2)O_(7),ClO_(3),Cl_(2)O,NaCl,Cl_(2),ClO_(2). Which oxidation state is not present in any of the above compounds ?

Find out the oxidation number of chlorine in the following compounds a

1.	Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine. NaClO_(4),NaClO_(3),NaClO,KClO_(2),Cl_(2)O_(7),ClO_(3),Cl_(2)O,NaCl,Cl_(2),ClO_(2). Which oxidation state is not present in any of the above compounds ?
Answer» Solution :`NaClO_(4):+1+Cl+4(-2)=0` `Cl=+7` `NaClO_(3):+1+Cl+3(-2)=0` `Cl=+5` `NaClO:+1+Cl-2=0` `Cl=+1` `KClO_(2):+1+Cl+2(-2)=0` `Cl=+3` `Cl_(2)O_(7):2Cl+7(-2)=0` `Cl=+7` `ClO_(3):Cl+3(-2)=0` `Cl=+6` `Cl_(2)O:2Cl-2=0` `Cl=+1` `NaCl:Cl=-1` `Cl_(2)` : Cl = 0 `ClO_(2)` : Cl + 2(-2) = 0 Cl = +4 Increasing order of oxidation number of Cl : `NaClltCl_(2)ltNaClOltKClO_(2)ltClO_(2)ltNaClO_(3)ltClO_(3)ltCl_(2)O_(7)` None of them possess (+2) oxidation STATE.