Find out the results of the following operations. (i) 117.3 xx 0.0024 (ii) 9.27 div 41 (iii) 42 xx 0.041 (iv) 124.2 + 52.487 (v) 124.2-52.487 (vi) sqrt(58.97)(vii) (17.5)^(2)

Find out the results of the following operations. (i) 117.3 xx 0.0024

1.	Find out the results of the following operations. (i) 117.3 xx 0.0024 (ii) 9.27 div 41 (iii) 42 xx 0.041 (iv) 124.2 + 52.487 (v) 124.2-52.487 (vi) sqrt(58.97)(vii) (17.5)^(2)
Answer» Solution :(i) 0.0024 has 2 significant figures. Hence 117.3 is rounded off to have `2+1= 3` significant figures. It becomes 117 only. Now `117 xx 0.0024 = 0.2808` This is to be rounded off to have two significant figures only. The result is 0.28. (ii) 41 has only 2 significant digits. Hence 9.27 can have `2 +1= 3` significant digits. It has 3 significant digits only. No need for ROUNDING off. `(9.27)/(41)= 0.2260975` This is to be rounded off to two significant digits. The result is 0.23. (iii) Both number have two significant digits `42 xx 0.041= 1.722`. This to be rounded off to 2 significant digits. The result is 1.7. (iv) As this is a sum, we have to CONSIDER decimal PLACES. 124.2 has only one decimal place. Hence 52.487 is to be rounded off to `1 + 1= 2` decimal places. It becomes as 52.487 = 52.49 Now `124.2 + 52.49= 176.69`. This is to be rounded off to one decimal place. The result is as 176.69= 176.7 (v) Here again, we have `124.2- 52.487= 124.52.49 = 71.71`. This is to be rounded off to one decimal place The result is 71.7 (vi) `sqrt(58.97)= 7.679`. This has got the same number of significant digits (4) as 58.97. (vii) `(17.5)^(2)= 306.25`. The original number 17.5 has only 3 significant digits. And hence the result will be 306 (Here we have to consider the significant figures).