1.

Find out the solubility product of CaF2 if solubility of CaF2 is 2.34 g/100 mL(a) 0.108 (mol/L)3(b) 0.072 (mol/L)3(c) 0.036 (mol/L)3(d) 0.032 (mol/L)3

Answer»

(a) 0.108 (mol/L)3

Solubility = 2.34/100 g/ml

Molar mass of CaF= 40 + 19 + 19 = 78 g/ml

Solubility in (mol/L = 2.34/78 x 1000/100 mol/L = 0.3mol / L

CaF\(\rightleftharpoons\) Ca2+ + 2F-

s   2s

Ksp = s x (2s)= 4 s3

Ksp = 4 x (0.3)3 = 0.108 (mol/L)3



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