Find out the value of K_(c) for each of the following equilibria from the value of K_(p) (a) 2 NOCl (g) hArr 2 NO(g) + Cl_(2) (g), K_(p) = 1*8 xx 10^(-2) " at 500 K " (b)CaCO_(3) (s) hArr CaO (s) hArr CaO(s) + CO_(2) (g), K_(p) = 167 "at" 1073 K.

Find out the value of K_(c) for each of the following equilibria from

1.	Find out the value of K_(c) for each of the following equilibria from the value of K_(p) (a) 2 NOCl (g) hArr 2 NO(g) + Cl_(2) (g), K_(p) = 1*8 xx 10^(-2) " at 500 K " (b)CaCO_(3) (s) hArr CaO (s) hArr CaO(s) + CO_(2) (g), K_(p) = 167 "at" 1073 K.
Answer» Solution :(a) ` Delta n_(g) = 3-2 =1 K_(p) = K_(c) (RT) or K_(c) =(K_(p))/(RT) = (18 xx 10^(-2))/(00831 xx 500) " " (R = 00831 "BAR litre MOL"^(-1) K^(-1))` ` = 4 33 xx 10^(-4) ` (b) ` Delta n_(g) = 1 - 0 = 1 , K_(c) = (K_(p))/ (RT)= (167)/(63 xx 10^(14))= 187 .`