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Find out the value of K_c for each of the following equilibria from the value of K_p : (i)2NOCl(g) hArr 2NO(g) + Cl_2(g) , K_p=1.8xx10^(-2) at 500 K (ii)CaCO_3(s) hArr CaO(s) +CO_2(g) , K_p = 167 at 1073 K |
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Answer» SOLUTION :`2NOCl hArr 2NO(G) + Cl_2(g)` `K_p = 1.8xx10^(-2)` at 500 K `Deltan` =3-2=1 `K_c=K_p(RT)^(-Deltan_g)` `=1.8xx10^(-2) (0.0831xx500)^(-1) =4.33xx10^(-4)` (II)`Deltan`=1-0=1 `K_c=K_p(RT)^(-Deltan_g)` `=167xx(0.0831xx1073)^(-1)` =1.87 |
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