1.

Find out the value of Kc from the value of Kp:2NOCl(g) ⇌ 2NO(g) + Cl2(g), Kp = 1.8 x 10-2 at 500 K

Answer»

KC = Kp(RT)-Δn

R = 0.082 L atm mol-1 K-1

For this reaction Δn = (2 + 1) - (2) = +1

Kc = Kp(RT)-1

= 1.8 x 10-2 x (0.082 x 500)-1 = 4.4 x 10-4



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