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Find p(0)for polynomial :p(y)=ysquare-y+1 |
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Answer» 1 ONE -1 P(y)=y2-y+1Put y=0P(0)=(0)2-0+1P(0)= 1 p(y) = y2 - y + 1p(0) = (0)2 - 0 + 1p(0) = 1 |
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