Find p(0), p(1) and p(-1) in the following polynomials,i. p(x) = 3x +

1.	Find p(0), p(1) and p(-1) in the following polynomials,i. p(x) = 3x + 5ii. p(x) = 3x2 + 6x + 1iii. p(x) = 2x2 – 3x + 4iv. p(x) = 4x3 + 2×2 + 3x + 7v. p(x) = 5x3 – x2 + 2x – 3
Answer» i. p(x) = 3x + 5 p(0) = 3 × 0 + 5 = 5 p(1) = 3 × 1 + 5 = 8 p(-1) = 3 x - 1 + 5 = 2 ii. p(x) = 3x² + 6x + 1 p(0) = 3 × 0² + 6 × 0 + 1 = 1 p(1) = 3 × 1² + 6 × 1 + 1 = 10 p(-1) = 3 × (-1)² + 6 × (-1) + 1 = -2 iii. p(x) = 2x² – 3x + 4 p(0) = 2 × 0² – 3 × 0 + 4 = 4 p(1) = 2 × 1² – 3 × 1 + 4 = 3 p(-1) =2 × (-1)² – 3 × (-1) + 4 = 9 iv. p(x) = 4x³ + 2x² + 3x + 7 p(0) = 4 × 0³ + 2 × 02 + 3 × 0 +7 = 7 p(1) = 4 × 1³ + 2 × 12 + 3 × 1 + 7 = 16 p(-1) = 4 × (-1)³ + 2 × (-1)² + 3 × (-1) +7 = 2 v. p(x) = 5x³ – x² + 2x – 3 p(0) = 5 × 0³ – 0² + 2 × 0 – 3 =-3 p(1) = 5 × 1³ – 1² + 2 × 1 – 3 = 3 p(-1) = 5 × (-1)³ – (-1)² + 2 × (-1) – 3 = -11

Find p(0), p(1) and p(-1) in the following polynomials,i. p(x) = 3x + 5ii. p(x) = 3x2 + 6x + 1iii. p(x) = 2x2 – 3x + 4iv. p(x) = 4x3 + 2×2 + 3x + 7v. p(x) = 5x3 – x2 + 2x – 3

Answer»

i. p(x) = 3x + 5

p(0) = 3 × 0 + 5 = 5

p(1) = 3 × 1 + 5 = 8

p(-1) = 3 x - 1 + 5 = 2

ii. p(x) = 3x² + 6x + 1

p(0) = 3 × 0² + 6 × 0 + 1 = 1

p(1) = 3 × 1² + 6 × 1 + 1 = 10

p(-1) = 3 × (-1)² + 6 × (-1) + 1 = -2

iii. p(x) = 2x² – 3x + 4

p(0) = 2 × 0² – 3 × 0 + 4 = 4

p(1) = 2 × 1² – 3 × 1 + 4 = 3

p(-1) =2 × (-1)² – 3 × (-1) + 4 = 9

iv. p(x) = 4x³ + 2x² + 3x + 7

p(0) = 4 × 0³ + 2 × 02 + 3 × 0 +7 = 7

p(1) = 4 × 1³ + 2 × 12 + 3 × 1 + 7 = 16

p(-1) = 4 × (-1)³ + 2 × (-1)² + 3 × (-1) +7 = 2

v. p(x) = 5x³ – x² + 2x – 3

p(0) = 5 × 0³ – 0² + 2 × 0 – 3 =-3

p(1) = 5 × 1³ – 1² + 2 × 1 – 3 = 3

p(-1) = 5 × (-1)³ – (-1)² + 2 × (-1) – 3 = -11