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Find p and q so that y p sin 3xcos 3x satisfy the equationdr4dx |
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Answer» dy/dx=3Acos3x-3bsin3xd2y/dx2= -9Asin3x-9bcos3x-9Asin3x-9bcos3x+4(3Acos3x-3bsin3x)+3(Asin3x+bcos3x)=10cos3x-9A-12b+3A=0=>-6A-12b=0=>A=-2b-9b+12A+3b=10=> -6b+12A=10=>-6b-24b=10=>-30b=10=>b=-10/30=-1/2so a= 2/3Ans a=2/3, b=-1/3 |
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